Answer:
520 people in 2 hours
rate = 260 people per hour
Step-by-step explanation:
change minutes to hours
15 minute* 1 hr/60 minutes = .25 hrs
65 people      x people
---------------  = ------------------
.25 hrs            2 hrs
using cross products
65 * 2 = .25 * x
130 = .25x
divide by .25
130/.25 = .25x/.25
520 =x
520 people
65 people      x people
---------------  = ------------------
.25 hrs            1 hrs
using cross products
65 = .25x
divide by .25
65/.25 = .25x/.25
260 =x
260 people in 1 hour
rate = 260 people per hour
 
        
             
        
        
        
Answer: (c) y<=-x+4
The area is shaded UNDER the boundary line, hence "<"
The boundary is plotted as solid line, hence "="
 
        
             
        
        
        
You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
        
             
        
        
        
Answer:
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Step-by-step explanation:
 
        
                    
             
        
        
        
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value 
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot. 
- Lowest amount of sale made by Latasha = 50 
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box. 
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution 
- IQR = Upper Quartile (Q3) - Lower quartile(Q1) 
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box) 
- Q1 = 150 (starting point of the box) 
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box) 
- Q1 = 100 (starting point of the box) 
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla. 
Learn more :brainly.com/question/24582786