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kvasek [131]
3 years ago
5

What is the probability that a point chosen at random in the given figure will be inside the larger circle and outside the small

er circle?
Enter your answer, as a fraction in simplest form, in the box.

P(inside larger circle and outside smaller circle) = _____

Mathematics
2 answers:
Yuki888 [10]3 years ago
8 0
<span>The probability that a point is chosen at random in the given figure is 40/49 or .82. The answer to the following statement or the missing blank is 40/49. The probability is the possibility of the occurrence or happening of something.</span>
nikdorinn [45]3 years ago
7 0

Answer: \frac{40}{49}

Step-by-step explanation:

Given: The radius of the larger circle = 14 cm

The area of a circle is given by :-

A=\pi r^2

The area of the larger circle will be :-

A=\pi (14)^2=196\pi cm^2

The radius of the smaller circle = 6 cm

The area of the smaller circle will be :-

A=\pi (6)^2=36\pi cm^2

The area of the part which belongs to the the larger circle and outside the smaller circle =Area of larger circle- Area of smaller circle

=196\pi-36\pi=160\pi cm^2

Now, the probability that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle is given by:-

\frac{160\pi}{196\pi}=\frac{40}{49}

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sergij07 [2.7K]

Answer:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

Step-by-step explanation:

Given

8x^{-10}y^6 - 2x^2y^{-8}

Required

Simplify

Rewrite as:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}

Take LCM

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Apply law of indices

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

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Answer:

Step-by-step explanation:

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