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wariber [46]
3 years ago
13

Rate our friendship pls will mark brainliest

Mathematics
1 answer:
Kryger [21]3 years ago
7 0

Answer:

out of 10?

Step-by-step explanation:

probably a 7-8? maybe 9?

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Find the sum of this problem.
IceJOKER [234]

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34

Step-by-step explanation:

i think

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2 years ago
Find all trigonometric functions of an angle θ in the third quadrant for which cos θ =(-5)/6
Tanzania [10]

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its 69 now answer ur phone tyvm

3 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY GEOMETRY HOMEWORK PLEASE?
Kay [80]

Answer:

Option A

Step-by-step explanation:

The complete question is shown in the attachment.

The sum of angles in a triangle is 180 degrees.

This implies that:

m\angle A+85+53=180

m<A+138=180

m<A=180-138=42

Now we use the sine rule to find AC=b

\frac{b}{\sin 85}=\frac{85}{\sin 42}

This implies that:

b=\frac{85}{\sin 42}*\sin 85

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2 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\&#10;y-5=\pm \sqrt{x-2}\\&#10;y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
2 years ago
Find the length of the third side of the right triangle
Maurinko [17]

Answer:

9

Step-by-step explanation:

        2       2

b + 8   = 17

b + 16 = 34

34 - 16 = 18

18 ÷ 2 = 9

4 0
3 years ago
Read 2 more answers
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