3 years ago

Pls help ASAP pls help

Mathematics

1 answer:

tatyana61 [14]3 years ago

4 0

Answer:

your just going to replace 0.1 to make the statements correct

Step-by-step explanation:

yan po ALAM ko

You might be interested in

HELP!!! A plumber charges a fee of $25 plus $30 per hour on the job. Make a table of values for the total charge depending on th

Effectus [21]

Answer:

Yes, this function can be defined by linear model.

Step-by-step explanation:

$\mathrm{Total\:=\:Fixed\:Fee\:+\:Hourly\:Rate\:\times Number\:of\:hours}$

$\mathrm{Linear:}\:\:T=\:$25+30h$

Best Regards!

3 0

2 years ago

A family spent a total of $1946 on fast food this year. If this family decreases the amount it spends on fast food by 3% every y

prohojiy [21]

1946 times 3/100=58.38
58.38 times 5 =291.9

1946-291.9=165.41
165.41 is the answer. Please mark brainliest.

8 0

3 years ago

Surface area of a box 12 x 6 x 9.5

Ber [7]

9514 1404 393

Answer:

486 square units

Step-by-step explanation:

Use the surface area formula with the given numbers.

SA = 2(LW +H(L +W))

SA = 2(12·6 +9.5(12 +6)) = 2(72 +9.5(18)) = 486

The surface area of the box is 486 square units.

4 0

3 years ago

Can someone help me? It's urgent and thank you!

nordsb [41]

Answer:

the first one

Step-by-step explanation:

3 0

2 years ago

Professor York randomly surveyed 240 students at Oxnard University and found that 150 of the students surveyed watch more than 1

BaLLatris [955]

Answer:

1727 students

Step-by-step explanation:

Here we have the formula for sample size given as

$n = \frac{p(1-p)z^2}{ME^2}$

Where:

p = Mean

ME = Margin of error = 3

z = z score

Therefore, we have

p = 150/240 = 0.625

z at 99 % = 2.575

ME = $\pm$ 3%

Therefore $n = \frac{0.625(1-0.625)2.575^2}{0.03^2} = 1726.73$

The number of students Professor York have to sample to estimate the proportion of all Oxnard University students who watch more than 10 hours of television each week within ±3 percent with 99 percent confidence = 1727 students.

5 0

3 years ago