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3 years ago

Jimmy ran at a speed of m miles. how far did he run in t minutes

Mathematics

1 answer:

beks73 [17]3 years ago

8 0

Answer:

(mxt) miles

Step-by-step explanation:

$speed = m \: miles \: per \:minute \\ time \: = t \: minutes \\ speed = \frac{distance}{time} \\ m = \frac{d}{t} \\ m \times t \: = d \\ d = (m \times t)miles$

hope that this is helpful.

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PLEASE HELP!!! DONT IGNORE ME!!!

MrRa [10]

1. 2x^2-x-15=0
A = 2
B = -1
C = -15

2. 10^2-2x=0
A = 10
B = -2
C = 0

3. x^2–3x-40=0
A = 1
B = -3
C = -40

4. x^2+3x-2=0
A = 1
B = 3
C = -2

5. 4x^2-17x+8=0
A = 4
B = -17
C = 8

Remember the equations should look like Ax^2+Bx+C=0 (in this order!!)

5 0

3 years ago

The Oregon trail is 2.197 miles long. How long would it take a covered wagon travelling 20 miles a day to complete the trip? Wri

Bess [88]

Answer: It needs 2.4 hours to complete the trip.

Step-by-step explanation:

Since we have given that

Length of Oregon trail = 2.197 miles

Speed at which it travel = 20 miles per day

we need to find the time taken by it ,

As we know that

$Time=\frac{Distance}{Speed}$

$Time=\frac{2.197}{20}\\\\Time=0.10\text{ days}$

So,

it will be changed into hours

$1\text{ day}=24\text{ hours}\\\\0.1\text{ day}=24\times 0.1=2.4\text{ hours}$

so, it needs 2.4 hours to complete the trip.

3 0

3 years ago

I need the angle of elevation

Aleksandr-060686 [28]

Answer:

multiply and see what you get

4 0

3 years ago

Will mark brainliest! Questions are in the picture!

alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the perimeter to the nearest tenth.

As we know that the area of triangle is ,

$\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)$

Substituting the respective values,

$\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0$

On using the Quadratic formula , we have;

$\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}$