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3 years ago

What is the slope of the line between (-3,6) and (-5,9)?

Mathematics

2 answers:

Margaret [11]3 years ago

3 0

the answer would be 3/-2.

Anettt [7]3 years ago

3 0

Answer:

3/-2

Step-by-step explanation:

You do the slop intercept form which is y2-y1/x2-x1

So it would be

y2=9

y1=6

9-6=3

x2=-5

x1=-3

-5+3=-2

so you get 3/-2

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-6x-7=4x-2. Can you show step by step explanation. thank u.

monitta

Answer:

x=-1/2

Step-by-step explanation:

-6x-7=4x-2

-6x-7+6x=4x+6x-2

-7=10x-2

-7+2=10x-2+2

-5=10x

-5/10=10x/10

x=-1/2

Hope this helps!

8 0

2 years ago

What is the annual share of the profit awarded to the owner of a share of stock called?

madam [21]

I think its common stock

5 0

3 years ago

Kareendeep has $168.50 in her bank account. She buys x shirts for $5.5o each. Write and solve an equation Kareendeep can use to

Vikentia [17]

Answer:

Equation: 5.5x = 168.5

Solution: 30 shirts

Step-by-step explanation:

First, create the equation where x is the number of shirts.

Since each shirt is $5.50, the cost of the shirts will be 5.50x

Set this equal to 168.50, since that is how much money Kareendeep has.

So, the equation will be 5.5x = 168.5

Now, solve this for x, the number of shirts she can buy:

5.5x = 168.5

Divide each side by 5.5

x = 30.6

Since we can only have a whole number of shirts, she can only buy 30 shirts.

So, the answer is 30 shirts.

5 0

3 years ago

PLEASE HELP ME!! this is due tonight and i really need help with this so i can do other assignments

Mamont248 [21]

Answer:

64cm² I think :) if u get it wrong dont blame it on me.

5 0

3 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago