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givi [52]
3 years ago
14

Sale amount is $12,500. Sales Tax is 5%. What is the new amount?

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

13,125.

Step-by-step explanation:

you do 12,500 times .05 = 625 then add 12,500 and 625 then you get 13,125

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A notebook costs $2.39 at Walmart. If the tax rate is 7%, what is the total cost at the register?
shusha [124]
$2.39 is 100%
$x is 7%

2.39 x 7 = 16,73
16,73/100 = 0,17
the total cost is $2,56
5 0
3 years ago
The isotope cobalt-60 has a nuclear mass of 59.933820 u
Anit [1.1K]

To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.

Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.

Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are

60-Z=60-27=33

From the question we know that the given nuclear mass is 59.933820 u.

Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.

Thus,

Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u

\therefore 27\times 1.007825+33\times 1.008665-59.933820=0.5634 u

Thus, the required Mass Defect is 0.5634u.

In eV, the Mass Defect is 931.5MeV\times 0.5634=534.807 MeV

6 0
3 years ago
Read 2 more answers
-5y + 12 + 8y − 6 − 2 = ______ help plz
Sladkaya [172]

Answer:

(combine like terms)

-5y + 12 + 8y − 6 − 2  

3y+12-8

3y+4

3 0
3 years ago
GUYS HELP!!!
Maurinko [17]
There isn’t enough information for us to help you:(
7 0
3 years ago
Read 2 more answers
A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
3 years ago
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