Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence
.
- The standard deviation is of 1 gram, hence
.
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:



The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213
Answer:
1,195,742.25 (final answer since instructions did not include rounding up or anything)
Step-by-step explanation:
n = 4
The given expression is:
9^8 ÷ 9n
USE PEMDAS order of operations and solve:
9^8 ÷ 9n
= 43046721 ÷ 9n
Substitue n with 4 and solve:
43046721 ÷ 9(4)
= 43046721 ÷ 36
= 1,195,742.25
T<span>he correct answers: </span>"a" and "c".
At "a" we have:
x= number of <span>unopened packages
</span>At "c" we have:
x= number of <span>hours that she works</span>
<span>To which set of numbers does −1.2 belong? </span>D.) rational numbers