The answer is 8.2 bc anything above a 5 goes up.
8.16 <<< a 6 is greater than 5. So the 1 goes up to a 2.
Answer:
B
Step-by-step explanation:
y = 
is the equation of a horizontal line parallel to the x- axis.
A line perpendicular to it will be a vertical line parallel to the y- axis with equation
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (- 6, - 9 ) with equation
x = - 6 → B
Answer:
let
hypotenuse[h]=60ft
base[b]=36ft
perpendicular [p]=48ft
by using Pythagoras law
p²+b²=h²
48²+36²=60²
2896≠3600
since p²+b²≠ h²[<u>so</u><u> </u><u>the</u><u> </u><u>stage</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>in</u><u> </u><u>a</u><u> </u><u>right</u><u> </u><u>angled</u><u> </u><u>tria</u><u>ngle</u><u>]</u><u>but</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>scalene</u><u> </u><u>triangle</u>
Answer:
Step-by-step explanation:
To solve this, we are going to make an age table:
Age Now Age 10 years ago
Tanya
Elliot
Filling the in the Age Now column comes from the first sentence. If Elliot is 2 times Tanya's age and we don't know Tanya's age, then Tanya's age is x and Elliot's age is 2x:
Age Now Age 10 years ago
Tanya x
Elliot 2x
Filling in the Age 10 years ago column simply requires that we take their ages in the Age Now column and subtract 10 from each age:
Age Now Age 10 years ago
Tanya x x - 10
Elliot 2x 2x - 10
Since the question is How old is Elliot now based on the fact that 10 years ago....blah, blah, blah, we are using the ages in the 10 years ago column to write our equation. It says:
10 years ago, Elliot was 4 times as old as Tanya. Translated into mathspeak:
2x - 10 = 4(x - 10) and
2x - 10 = 4x - 40 and
-2x = -30 so
x = 15. That means that Elliot is 30 and Tanya is 15
8/10 because 8 is on the tenths place so all you have to do is put it over 10.
