Answer:
Oxidation of ammonia
Explanation:
Chemical equation:
NH₃ + O₂ → NO + H₂O
Balanced chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
The given reaction shows the oxidation ammonia. When oxygen react with ammonia it form nitrogen monoxide and water vapors. Nitrogen monoxide decomposes in air.
It can be seen that the given reaction also follow the law of conservation of mass. There are four nitrogen, ten oxygen and twelve hydrogen atoms on both side of equation.
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Answer:
D. Phototropism
Explanation:
Plants, like every other living organism, responds to external stimulus. In this question, the stimulus is LIGHT from the sun entering through the window sill. The plant is responding positively to the light stimuli by growing towards the direction where the light is coming from. This exhibit is called PHOTOTROPISM.
Phototropism, comes from two words viz photo- meaning light and tropism- meaning movement. Hence, phototropism is the growth of an organism (plant in this case) in response to a light stimulus. The case described in this question is POSITIVE PHOTOTROPISM because the growth occurs towards the light source.
Amphetamine was developed initially as a substitute for a closely-related chemical derived from the Chinese herb ma huang. That chemical is Ephedrine.
<h3>
What is Ephedrine?</h3>
Ephedrine is a stimulant medication that can be considered an amine chemical compound and substituted amphetamine.
Ephedrine is used in sports to stimulate the central nervous system (C_NS) and as energy supplier.
Ep_hedrine use is prohibited and chronic usage of this substance may have problems the health.
Learn more about Ephedrine here:
brainly.com/question/1122074
Answer:

Explanation:
Hello,
In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

That in terms of the heat capacities, masses and temperature changes turns out:

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Best regards.
Answer:
i think the answer is C
Explanation:
not sure plsss dont bash im a beginner