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3 years ago

A student is performing experiments on a particular substance. Which

Chemistry

2 answers:

sesenic [268]3 years ago

4 0

Explanation:

it reacts with acid .......

WINSTONCH [101]3 years ago

4 0

I think answer should d. Please give me brainlest let me know if it’s correct or not okay thanks bye

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What is the mass (grams) of 9.89 * 10^24 moles of (cho30h)?

vladimir2022 [97]

43 grams of moles cho30h

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3 years ago

What is the mass of 2 moles of nitrogen gas, N2?

drek231 [11]

Answer:

28g

Solution. Hence, 2 moles of nitrogen atoms weigh 28g.

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3 years ago

What is the correct definition of energy?

scoray [572]

Answer:

The ability to do work

Explanation:

Energy refers to the ability to carry out work.
It is measured in Joules (J).
Energy may exist in different forms such as potential energy when a body is at rest, kinetic energy when the body is in motion, etc.
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3 years ago

Read 2 more answers

A nitrde ion has 7protons,8nutrons and 10 electrons. what is the overall change

Rama09 [41]

Answer:

the overall charge on the nitride anion is

( 3 − ) .

N power 3 − → the nitride anion

6 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago