20600Cal
Explanation:
Given parameters:
Mass of water = 319.5g
Initial temperature = 35.7°C
Final temperature = 100°C
Unknown:
Calories needed to heat the water = ?
Solution:
The calories is the amount of heat added to the water. This can be determined using;
H = m c Ф
c = specific heat capacity of water = 4.186J/g°C
H is the amount of heat
Ф is the change in temperature
H = m c (Ф₂ - Ф₁)
H = 319.5 x 4.186 x (100 - 35.7) = 85996.56J
Now;
1kilocalorie = 4184J
85996.56J to kCal; 
= 20.6kCal = 20600Cal
learn more:
Specific heat brainly.com/question/3032746
#learnwithBrainly
Explanation:
There are two direct factors that affect solubility: temperature and pressure. Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.
Carbon Dioxide + Water --> Glucose + Oxygen + Energy(ATP)
Also photosynthesis only takes place in plant cells due to the fact that they are autotrophs and make their own food.
Reactants: Carbon Dioxide + Water
Products: Glucose, Oxygen, and Energy
day and night is the main way you can tell as well as the stars moving across the sky, and we can tell it rotates by looking at the sky and seeing the sun move across the sky during the day.
