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Mekhanik [1.2K]
2 years ago
14

Calculate each of the following quantities:

Chemistry
1 answer:
balandron [24]2 years ago
5 0

The number of moles in 78.9 g of sodium perchlorate is 0.644 moles and 3.876 x 10²³ formula units are particles.

<h3>What are formula units?</h3>

Moles are converted to formula units by multiplying them by 6.02 x 1023, or Avogadro's number (Na). The moles and masses of tiny particles are estimated using this method.

Given that the mass of sodium perchlorate is 78.9 g

The molar mass of sodium perchlorate is 122.44 g/mol

Moles of sodium perchlorate will be

Moles (n) = mass ÷ molar mass

n = 78.9 g  ÷ 122.44

n = 0.644  moles

If 1 mole = 6.02 x 10²³

Then, 0.644 moles = 3.876 x 10²³ particles

Thus, there are 0.644 moles of sodium perchlorate in 78.9 g.

Learn more about formula units, here:

brainly.com/question/15488332

#SPJ4

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Anna11 [10]

Answer:

Amino Acids

Explanation:

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8 0
3 years ago
Giving one KG equals 2.20 pounds how many kilograms are in 338 pounds
dezoksy [38]

Answer:

154 kg

Explanation:

Step 1: Define conversion

1 kg = 2.20 lbs

Step 2: Use Dimensional Analysis

338 \hspace{3} lbs(\frac{1 \hspace{3} kg}{2.20 \hspace{3} lbs} ) = 153.636 kg

Step 3: Simplify

We are give 3 sig figs.

153.636 kg ≈ 154 kg

7 0
4 years ago
What mass of calcium chloride will be produced from 4.09 g of hcl reacting with ca(oh)2
natka813 [3]
5.52g Calcium Chloride
7 0
3 years ago
Read 2 more answers
if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many gram
Romashka-Z-Leto [24]

Answer:

Mass of CO₂ produced  = 5.72 g

Explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles =  2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

                         CH₄             :              CO₂

                           1                 :              1

                        0.146            :           0.146

                         O₂                :               CO₂

                          2                 :                   1

                     0.26                :              1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol ×  44 g/mol

Mass = 5.72 g

4 0
3 years ago
Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of CH4 is required to completely react with 100 grams of
Amanda [17]
2 O2 + CH4 CO2 + 2 H2O 

<span>What mass of CH4 is required to completely react with 100 grams of O2? </span>

<span>mass CH4 = 100 g O2 x (1 mol O2 / 32 g) x (1 mol CH4 / 2 mol O2) x (16.05 g / 1 mol CH4) </span>
<span> 25 grams CH4 


</span>
5 0
3 years ago
Read 2 more answers
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