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zvonat [6]
3 years ago
7

At 20°C the vapor pressure of benzene (C6H6) is 75 torr, and that of toluene (C7H8) is 22 torr. Assume that benzene and toluene

form an ideal solution. What is the composition in mole fractions of a solution that has a vapor pressure of 40. torr at 20°C?
Chemistry
1 answer:
valina [46]3 years ago
8 0

Answer: The mole fraction of benzene will be 0.34 and mole fraction of toluene is 0.66

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

p_1=x_1p_1^0 and p_2=x_2P_2^0

where, x = mole fraction in solution

p^0 = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2\\p_{total}=x_{benzene}p_{benzene}^0+x_{toluene}P_{toluene}^0

x_{benzene}=x,

x_{toluene}=1-x_{benzene}=1-x,

p_{benzene}^0=75torr

p_{toluene}^0=22torr

p_{total}=40torr

40=x\times 75+(1-x)\times 22

x=0.34

Thus (1-x0 = (1-0.34)=0.66

Thus the mole fraction of benzene will be 0.34 and that of toluene is 0.66

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