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Annette [7]
3 years ago
8

The hydrolysis of sucrose (C12H22O11) into glucose and fructose in acidic water has a rate constant of 1.8×10−4s−1 at 25 ∘C. Ass

uming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.55 L of a 0.160 M sucrose solution is allowed to react for 200 minutes.
Chemistry
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

Mass of sucrose that is hydrolyzed = 123.55 g

Explanation:

Since the reaction is a first ofree reaction,

Let the initial concentration of sucrose be C₀

And the concentration of sucrose left at any time be C.

r = (dC/dt) = -kC (Minus sign because it's a rate of reduction)

K = rate constant

(dC/dt) = - kC

(dC/C) = -kdt

 ∫ (dC/C) = -k ∫ dt 

Solving the two sides as definite integrals by integrating the left hand side from C₀ to C and the Right hand side from 0 to t.

We obtain

In (C/C₀) = -kt

(C/C₀) = (e⁻ᵏᵗ)

C = C₀ e⁻ᵏᵗ

So, we can find the concentration of sucrose left at the given time

k = 1.8 × 10⁻⁴ s⁻¹

t = 200 minutes = 200 × 60 = 12000 s

kt = 12000 × 1.8 × 10⁻⁴ = 2.16

C₀ = 0.160 M

C = 0.160 e⁻²•¹⁶ = 0.01845 M

So, the concentration that has been used up = 0.160 - 0.01845 = 0.142 M

To calculate the mass of sucrose that has reacted, we'll convert the concentration used up into number of moles.

Concentration = (number of moles)/(volume in Litres)

number of moles = concentration × volume in Litres

Volume in Litres = 2.55L

Number of moles = 0.142 × 2.55 = 0.361 moles

Then, mass = number of moles × Molar mass

Molar mass of sucrose = 342.3 g/mol

Mass of sucrose used up = 0.361 × 342.3 = 123.55 g

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Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

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3 years ago
In which regions of the atmosphere does temperature increase as altitude increases
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Answer:

<h2>stratosphere</h2>
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5 0
3 years ago
Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,
vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

N=n\times N_A

Where : N = Number of atoms

n = moles

N_A=6.022\times 10^{23} = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol ×  44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol ×  8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol

Mass percentage of gold :

\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=33.35 \%

Mass percentage of silver:

\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=62.80\%

Mass percentage of copper :

\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=3.85\%

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3 years ago
I need help ASAP! How many reactants and products are in each element according to the chemical equation above.
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Answer:

O 4

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Explanation:

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How are air pressure and temperature related during this time period?
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Answer:

B

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