Row A: x = 3
y = 2x - 3
y = 2(3) - 3 = 3 This is correct
Row B: x = 5
y = 2x - 3
y = 2(5) - 3 = 7 This is correct
Row C: x = 7
y = 2x - 3
y = 2(7) - 3 = 11 this is correct
Row D: x = 10
y = 2x - 3
y = 2(10) - 3 = 17 THIS IS INCORRECT, SO ROW D
X^3 + 5^3
(x+5)x(x^2-X x 5+5^2)
(x+5)x(x^2 -5x+5^2)
(x+5)x(x^2 -5x+25)
(x+5) x (x^2 -5x+25)
1x9000
3x3000
2x4500
I hope this is what you are looking for
Answer:
Step-by-step explanation:
If you are always included to lead, that leaves 10 students to choose from.
If all that is important is being selected, then there are 10C3 = 120 ways to choose them.
If each selection has a unique duty, then there are 10P3 = 720 ways to assign them their jobs.
