A-(5,-9) B-(-9,-5) C-(-9,5) D-(-5,9) ASAP HELP!!! WILL MARK BRAINLIST!!!

We know that the area of the tile is 18 $\sqrt{3}$ and it makes a triangle, we also know the base and height. In this case the base is 2 $\sqrt{3}^{x/12}$ and the height is also given which is $\sqrt{3}^{\frac{x}{6} }$ .

Area of triangle = $\frac{bh}{2}$ ,

substituting we will end up with 18 $\sqrt{3}$ =( 2 $\sqrt{3}^{x/12}$ * $\sqrt{3}^{\frac{x}{6} }$ ) / 2

Here is the tricky part $\sqrt{x} = x^{\frac{1}{2} }$ , i totally forgot about that lol.

Simplifying: we will get 18 $\sqrt{3}$ = $3^{\frac{x}{8} }$

Now, in order to find the x, we will need to take the log of both sides.

$log18\sqrt{3} = \frac{x}{8} log3$

Solving for x we end up getting:

$8\frac{log18\sqrt{3} }{log3}$ = x

where x = 25.047.

To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

5 0

2 years ago

The diagram below shows the graph of the quadratic function f (x) = ax² + 8x + c. calculate the value for each of the following.

Alexxandr [17]

Answer:

see explanation

Step-by-step explanation:

The y- intercept is at (0, 6) ⇒ c = 6

The x- coordinate of the vertex is at the midpoint of the zeros, that is

m = $\frac{-3-1}{2}$ = $\frac{-4}{2}$ = - 2

Since the zeros are x = - 3 and x = - 1 then the factors are (x + 3), (x + 1) and

f(x) = a(x + 3)(x + 1) = a(x² + 4x + 3)

Comparing with f(x) = ax² + 8x + 6 ⇒ a = 2

Thus

f(x) = 2x² + 8x + 6

Substitute m = - 2 into the equation for value of n

n = 2(- 2)² + 8(- 2) + 6 = 8 - 16 + 6 = - 2

Hence

c = 6, m = - 2, a = 2, n = - 2

3 0

2 years ago

Read 2 more answers

A triangle has sides with lengths of 65 in 72 in and 97 in is it a right triangle?

Ray Of Light [21]

Answer:

yes

Step-by-step explanation:

By pythagoras' theorem,

97^2 = 9409

65^2 + 72^2 = 9409

since 65^2 + 72^2 = 97^2, the triangle is a right angled triangle

This is a question on Pythagoras theorem. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

6 0

2 years ago