All categories

2 years ago

Help please i am being timed

Chemistry

2 answers:

-BARSIC- [3]2 years ago

7 0

Answer:

Explanation:

got it wrong on edge2020

Lesechka [4]2 years ago

5 0

Answer:

its c because the northern and southern hemisphere get the same amount of energy from the son in march

You might be interested in

Which statement is true about a base when it reacts with another substance?

Nostrana [21]

Answer: a. It receives a hydrogen ion.

Explanation: Base is a species which is capable of donating its negative quantity and accepting the positive one.

For example, ammonia is considered as a base because it is capable of donating its lone pairs of electrons and can accept an proton as well.

Here, out of the given options, Hydrogen $H^{+}$ is a proton which is acting as a positive species and hydroxide ion $OH^{-}$ is a negative species.

Thus, option (A) is the correct answer as it will receive a hydrogen ion from another base making itself a conjugate acid.

4 0

3 years ago

Read 2 more answers

High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie

kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically, Molality = $\frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}$

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = $\frac{0.001002 g/L}{17 g/mol}$

= $5.89 \times 10^{-4}$ mol/L

Also, density = $\frac{1 g}{mL}$ = 1 kg/L

Therefore, molality will be calculated as follows.

Molality = $\frac{5.89 \times 10^{-4} mol/L}{1 kg/L}$

= $5.89 \times 10^{-4} mol/kg$

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = $\frac{0.000412 g/L}{46 g/mol}$

= $8.956 \times 10^{-6}$ mol/L

And, density = $\frac{1 g}{mL}$ = 1 kg/L

Hence, molality = $\frac{8.956 \times 10^{-6} mol/L}{1 kg/L}$

= $8.956 \times 10^{-6}$ mol/kg

Now, Molar mass of nitarte = 62 g/mol

Concentration = 1352.2 mg/L

= $\frac{1.3522 g/L}{62 g/mol}$

= 0.02181 mol/L

Also, density = $\frac{1 g}{mL}$ = 1 kg/L

Hence, molality will be calculated as follows.

Molality = $\frac{0.02181 mol/L}{1 kg/L}$

= 0.02181 mol/kg

Therefore, molality of given species is $5.89 \times 10^{-4} mol/kg$ for ammonia, $8.956 \times 10^{-6}$ mol/kg for nitrite, and 0.02181 mol/kg for nitrate ion.

7 0

3 years ago

si el calor fuese un fluido ¿en algun momento se agotaria después de que dos objetos se frotaran mutuamente?

rjkz [21]

Si el calor fuese un fluido no se agotaría, solamente cambiaría su forma o localización.

<h3>¿Qué ocurre cuando dos objetos con diferente temperatura están en contacto?</h3>

Cuando dos objetos de diferente temperatura están en contacto el calor fluye del objeto con mayor temperatura o más caliente, al objeto con menor temperatura o más frío. Esto ocurre hasta que ambos objetos alcanzan la misma temperatura.

<h3>¿Qué sucede con el calor?</h3>

El calor o energía termina se disipa hacia el entorno o la atmosfera cuando un cuerpo se enfría o hacia otro cuerpo si hay transferencia de calor, sin embargo, el calor no desaparece debido a la ley de la conservación de la energía y materia.

<h3>¿Qué sucedería si el calor fuera un fluido?</h3>

Si el calor fuera un fluido este fluido no desaparecería ni se agotaría, solamente se podría disipar a la atmósfera o ambiente.

Aprenda más sobre calor en: brainly.com/question/15890992

8 0

2 years ago

Where does the energy for almost all ecosystems come from

bonufazy [111]

The Sun is the major source of energy for organisms and the ecosystems of which they are a part. Producers such as plants, algae, and cyanobacteria use the energy from sunlight to make organic matter from carbon dioxide and water. This establishes the beginning of energy flow through almost all food webs.

4 0

3 years ago

Which is NOT a component of galaxies? * F. Universe G. Stars H. Dust J. Planets

Afina-wow [57]

Answer:

F. Universe

Explanation:

Universe and Galaxies are two different things.

4 0

2 years ago