All categories

3 years ago

What parts do all cells have?

Chemistry

2 answers:

aleksandr82 [10.1K]3 years ago

7 0

Answer:

All cells have these four parts in common: a plasma membrane, cytoplasm, ribosomes, and DNA

Explanation:

can i get brainliest plz

Ray Of Light [21]3 years ago

3 0

DNA cytoplasms ribosomes plasma membrane

You might be interested in

How do plants and animals differ in how they get food?

Vilka [71]

Animals get their food by preying on other species or scrounging for scraps they can find. Some eat other animals and some eat plants.
Plants get their food by absorbing minerals and water from the ground and absorbing carbon dioxide from the air through their leaves. They then also absorb sunlight and all of those components are made into food for the plant. Simple answer is through photosynthesis.

3 0

2 years ago

How is heat transferred when a person holds an ice pack?

Darina [25.2K]

I’m pretty sure it’s b.

8 0

3 years ago

a pot is filled with soup. the soup at the bottom of the pot is warmed by the stove burner, but how does the soup at the top get

Fudgin [204]

The heated soup moves to the tip by convection

7 0

4 years ago

A 150.0 mL sample of a 1.50 M solution of CuSO4 is mixed with a 150.0 mL sample of 3.00 M KOH in a coffee cup calorimeter. The t

svp [43]

Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225
mols KOH = 3.00 x 0.150 = 0.450 
specific heat solns = specific heat H2O = 4.18 J/K*C 

CuSO4 + 2KOH = Cu(OH)2 + 2H2O 
q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T 
q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) 
dHrxn in J/mol= q/0.225 mol CuSO4 
Then convert to kJ/mol

5 0

4 years ago

Read 2 more answers

The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25

sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

$Q=mc\Delta T$

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL = 4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

$Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal$

1 calorie = 4.184 J

$Q=\frac{340,956.75}{4.184} J = 81,490.62 J$

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0

3 years ago