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AleksandrR [38]
3 years ago
14

What is the energy of a photon that emits a light of frequency 6.42 x 1014 Hz?​

Chemistry
2 answers:
Dmitrij [34]3 years ago
8 0

Answer:

B. 4.25 x 10-19J is correct via a p e x

Explanation:

svetlana [45]3 years ago
3 0

Answer:

Option B. 4.25×10¯¹⁹ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 6.42×10¹⁴ Hz

Energy (E) =?

Energy and frequency are related by the following equation:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

With the above formula, we can obtain the energy of the photon as follow:

Frequency (f) = 6.42×10¹⁴ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 6.42×10¹⁴

E = 4.25×10¯¹⁹ J

Thus, the energy of the photon is 4.25×10¯¹⁹ J

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Afina-wow [57]

Answer:

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Explanation:

Given parameters:

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Unknown:

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Solution:

To solve this problem, we use the expression below;

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Now insert the parameters and solve for E;

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Answer:

A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.

 

You need to apply the ideal gas law PV=nRT

 

You have the pressure, P=1.01 atm

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Explanation:

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