Hello:
Balanced equation:
2 Na + FeBr2 = 2 NaBr + Fe
Reaction type: single replacement
Hope that helps!
Use the formula PV=NRT to find the amount of moles of nitrogen gas. Then use the same formula using the amount of moles found to find the temperature
Answer:
<em>Your</em><em> </em><em>answer </em><em>is</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>attachment</em><em>.</em><em> </em><em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em> </em><em>Stay</em><em> </em><em>blessed</em><em>.</em><em> </em>
Answer:
16.46 g.
Explanation:
- It is a stichiometry problem.
- We should write the balance equation of the mentioned chemical reaction:
<em>2Cu + Zn(NO₃)₂ → Zn + 2Cu(NO₃).</em>
- It is clear that 2.0 moles of Cu reacts with 1.0 mole of Zn(NO₃)₂ to produce 1.0 mole of Zn and 2.0 moles of Cu(NO₃).
- We need to calculate the number of moles of the reacted Cu (32.0 g) using the relation:
<em>n = mass / molar mass</em>
- The no. of moles of Cu = mass / atomic mass = (32.0 g) / (63.546 g/mol) = 0.503 mol.
<u><em>Using cross multiplication:</em></u>
2.0 moles of Cu produces → 1.0 mole of Zn, from the stichiometry.
0.503 mole of Cu produces → ??? mole of Zn.
- The no. of moles of Zn produced = (1.0 mol)(0.503 mol) / (2.0 mol) = 0.2517 mol.
∴ The grams of Zn produced = no. of moles x atomic mass of Zn = (0.2517 mol)(65.38 g/mol) = 16.46 g.