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Lorico [155]
3 years ago
10

What is the total cost if Jamil uses the pool on 6 days? Explain how to use the equation to find the cost.​

Mathematics
1 answer:
morpeh [17]3 years ago
8 0
I don’t even know is there any more details you can give
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Floyd weigh 160 pounds and is gaining 5 pounds per month. John weighs 140 pounds
Marizza181 [45]
It will take 4 months
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3 years ago
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Draw the triangle with vertices a(1, 1), b(5, 3), c(1, 7). find the parametrization, including endpoints, and sketch to check. (
Firlakuza [10]
Part A:

The parametric equations x=x_1+(x_2-x_1)t and y=y_1+(y_2-y_1)t where 0\leq t\leq1 describes the line segment that joins the points (x_1,\ y_1) and (x_2,\ y_2).

The parameterization of the line joining points A(1, 1) and B(5, 3) are given by substituting x_1=1,\ \ y_1=1,\ \ x_2=5,\ \ y_2=3.

Thus, we have

x = 1 + (5 - 1)t = 1 + 4t
y = 1 + (3 - 1)t = 1 + 2t

Therefore, the parameterization of line joining points A(1, 1) and B(5, 3) are x = 1 + 4t and y = 1 + 2t.



Part B:

The parametric equations x=x_1+(x_2-x_1)t and y=y_1+(y_2-y_1)t where 0\leq t\leq1 describes the line segment that joins the points (x_1,\ y_1) and (x_2,\ y_2).

The parameterization of the line joining points B(5, 3) and C(1, 7) are given by substituting x_1=5,\ \ 
y_1=3,\ \ x_2=1,\ \ y_2=7.

Thus, we have

x = 5 + (1 - 5)t = 5 - 4t
y = 3 + (7 - 3)t = 3 + 4t

Therefore, the parameterization of line joining points B(5, 3) and C(1, 7) are x = 5 - 4t and y = 3 + 4t.



Part C:

The parametric equations x=x_1+(x_2-x_1)t and y=y_1+(y_2-y_1)t where 0\leq t\leq1 describes the line segment that joins the points (x_1,\ y_1) and (x_2,\ y_2).

The parameterization of the line joining points C(1, 7) and A(1, 1) are given by substituting x_1=1,\ \ 
y_1=7,\ \ x_2=1,\ \ y_2=1.

Thus, we have

x = 1 + (1 - 1)t = 1
y = 7 + (1 - 7)t = 7 - 6t

Therefore, the parameterization of line joining points A(1, 1) and B(5, 3) are x = 1 and y = 7 - 6t.
8 0
3 years ago
How do I do this plz help me out
Nataliya [291]
It's saying that B is equal to 1, and c is equal to 4. So your gonna square B (multiply it by itself) and add c. Make sense?
6 0
3 years ago
Plz help correct answer gets brainliest.
Leona [35]

whats the question?????

3 0
2 years ago
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Lines k and p are perpendicular, neither is vertical and p passes through the origin. Which is greater? A. The product of the sl
AlladinOne [14]
What do we know about those two lines?

They are perpendicular, meaning they have the same slope.
We know the slope of both is not zero (neither is vertical).
Therefore either
1) Both slopes are positive and therefore the product is positive
2) Both slopes are negative and therefore the product is positive (minus by a minus is a plus)

For the y intercepts, we know that the line P passes through the origin.
Therefore its Y intercept is zero.
[draw it if this is not obvious and ask where does it cross the y axis]
Therefore the Y intercept of line K and line P is zero.
[anything multiplied by a zero is a zero]

So we know that the product of slopes is positive, and we know that the product of Y intercepts is zero.
So the product of slopes must be greater.
Answer A
4 0
3 years ago
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