Completing the square goes back to pythagorean thm but the way u do it, u want to find a value that enable u to take sqrt of both sides and solve x^2-8x+3=0 x^2-8x=-3 we need (x-4)^2 so add 16 (x-4)^2=-3+16 (x-4)^2=13 x-4=sqrt13 x=4(+/-)sqrt13
A) The total surface area of the rectangular prism minus the area of the rectangular base plus the total area of the rectangular pyramid minus the area of the rectangular base.
B) the total volume of the rectangular prism and the rectangular pyramid.
