Answer:
Whenever I'm alone with you
You make me feel like I am home again
Whenever I'm alone with you
You make me feel like I am whole again
Whenever I'm alone with you
You make me feel like I am young again
Whenever I'm alone with you
You make me feel like I am fun again
However far away
I will always love you
However long I stay
I will always love you
Related
Whatever words I say
I will always love you
I will always love you
Whenever I'm alone with you
You make me feel like I am free again
Whenever I'm alone with you
You make me feel like I am clean again
However far away
I will always love you
However long I stay
I will always love you
Whatever words I say
I will always love you
I will always love you
However far away
I will always love you
However long I stay
I will always love you
whatever words I say
I will always skrrt you
I'll always love you
SASAGEYO SASAGEYO SHINZOU WO SASAGEYO
I'll always love you
I love you
-Adele
Step-by-step explanation:
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
I don't really understand the question
√x + 9 - 4 = 1
√x + 5 = 1
√x = -4
√x = √-4
x = 2i
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ± 
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71
[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
