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denis23 [38]
3 years ago
7

Solve for x in the triangle. round your answer to the nearest tenth

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

x = 6.4

Step-by-step explanation:

Since you are given adjacent and hypotenuse use sin 53 = add/hyp

So .79863551 = x/8 so x = 6.3891

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The question is below
Digiron [165]

Answer:

(a) Stops, turns around and starts travelling back towards home.

(b) 8 km/hour.

Step-by-step explanation:

(b) Jo travels 4 kilometres in 1/2 hour = 9 km/hour.

8 0
4 years ago
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Jim Debt was reviewing the total accounts receivable. This month he received $80,000 from Credit customers. This represented 40
Lena [83]
<span>4x = 80,000 x= 80,000/.4 x = 200,000</span>
5 0
3 years ago
All the place value of 12,354.897
frutty [35]
All the place values of 12, 354.897 are as follows: 12 thousands, 3 hundred, 5 tens, 4 ones, 0.8 tenths .09 hundredths, .007 thousandths.
4 0
3 years ago
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a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh
sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

h=-16t^2+32t+48

Let us assume that we need to find the time by it to reach the ground. It means h = 0

-16t^2+32t+48=0

The above is a quadratic equation. The value of t is given by :

t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s

So, it will take 2.11 seconds to reach the ground.

6 0
3 years ago
Find the distance between (-7,-2) and (11,3)
jarptica [38.1K]

Answer:

The answer is

<h2>\sqrt{349}  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }   \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-7,-2) and (11,3)

The distance between the points is

<h3>d =  \sqrt{ ({ - 7 - 11})^{2} +  ({ - 2 - 3})^{2}  }  \\  =  \sqrt{ ({ - 18})^{2} +  ({ - 5})^{2}  }  \\  =  \sqrt{324 + 25}  \\</h3>

We have the final answer as

<h3>\sqrt{349}  \:  \: units</h3>

Hope this helps you

5 0
3 years ago
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