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goblinko [34]
3 years ago
7

Someone plz help me giving brainliest

Mathematics
1 answer:
agasfer [191]3 years ago
8 0

Answer:

from the left the right it should look like this;

4, 1, 2800, 7, 400

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How much total wrapping paper does it take to wrap two gifts: one with the dimensions of 6 cm by 10 cm by 9.5 cm and the other w
zhuklara [117]

Answer:

gift 1:

424 cm^2

570 cm^3

gift 2:

1420.5 cm^2

3622.5 cm^3

Step-by-step explanation:

We have to calculate the surface area of these gifts in order to know the amount of wrapping paper.

The formula for the surface area is:

A = 2*ab + 2*ac + 2*bc

Gift 1:

A = 2*6*10 + 2*6*9.5 + 2*10*9.5

A = 424 cm^2

That means that gift 1 needs 424 cm^2 of wrapping paper

Gift 2:

A = 2*14*17.25 + 2*14*15 + 2*17.25*15

A = 1420.5 cm^2

That means that gift 2 needs 1420.5 cm^2 of wrapping paper

Now, to calculate the cubic centimeters of packaging peanuts, we calculate the volume, the volume has as formula:

V = a*b*c  

Gift 1:

V = 6*10*9.5  

V = 570 cm^3

This means that gift 1 needs 570 cm^3 of packaging peanuts

Gift 2:

V = 14*17.25*15  

V = 3622.5 cm^3

That means that gift 2 needs 3622.5 cm^3 of packaging peanuts

5 0
3 years ago
What is zero property power
krok68 [10]
<span> When raising an number to zero power you will always get 1.  you raise both the numerator and the denominator</span>
6 0
3 years ago
The high temperatures for 8 days are shown. 48,42,44,49,58,31,58,46. Which measures of central tendency BEST describes the data
Troyanec [42]

Answer:

47 and the median

Step-by-step explanation:

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3 years ago
Find the probability of a student being 34 years old or younger. Express your answer as a percent
yarga [219]

Answer:

79%

Step-by-step explanation:

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3 years ago
Elias was given a lock for his school locker. The lock contains numbers between
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Answer:

34,220

Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

\binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{60}{3}=\frac{60!}{3!(60-3)!}\\\\\binom{60}{3}=\frac{60!}{3!(57)!}\\\\\binom{60}{3}=\frac{60*59*58}{3*2*1}\\ \\\binom{60}{3}=34220

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.

6 0
2 years ago
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