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Alja [10]
3 years ago
14

Which two expressions are equivalent? B. A 4(2 + x) 4.2 +2.x 4 + 2 + x (4 + 2) + X D. C. 4. X + 2 4. (x + 2) 4 = (2-x) 4- 2 = X​

Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0
I think it’s B because it’s in the right for mate
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You
saul85 [17]

Answer:

$29,005.97

Step-by-step explanation:

Cn = Co * (1 + i)^n

Cn = 104,986.99(1+.05/1)^(1*5)

Cn = 104,986.99(1+.05)^5

Cn = 104,986.99(105)^5

Cn = 104,986.99(1.2763)

Cn = 133,992.96, total money at end

133,992.96-104,986.99= $29,005.97, interest accumulated

4 0
3 years ago
Will give brainliest to correct! “Write the equation of the line.”
viktelen [127]

Answer: y=1/3x-2

Step-by-step explanation:

y=Mx+b

1/3 is rise over run

-2 is the y intercept

8 0
3 years ago
what would be a real world problem situation that you can write either a percent as a decimal or write a decimal as a percent
love history [14]
When grading papers you can convert decimals into percents

7 0
3 years ago
What are the factor of pair of number?
Sedbober [7]
C…………………………x Mmmmmvvtvjvj I j I
8 0
3 years ago
1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t
Mazyrski [523]

Answer:

Part (A): The required inequality is T < 35 or t >40.

Part (B): The correct option is C) Only x=7.

Part (C) |x+1|+5=2 has no solution; |4x+12|=0 has one solution; |3x|=9 has two solution.

Step-by-step explanation:

Consider the provided information.

Part (A)

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

15| x-7|+4-4=10|x-7|+4-4

Subtract 10|x-7| from both sides

15\left|x-7\right|-10\left|x-7\right|=10\left|x-7\right|-10\left|x-7\right|

5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

\left|x+1\right|+5=2

Subtract 2 from both sides.

\left|x+1\right|=-3

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

|4x+12|=0

4x+12=0

x=-3

Hence, |4x+12|=0 has one solution.

|3x|=9

\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a

3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3

Hence, |3x|=9 has two solution.

3 0
3 years ago
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