HELP WITH 20 PLEASE!

Mathematics

1 answer:

Marina86 [1]2 years ago

5 0

Area =base / height is the other way you can figure it out

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Find the missing side length

DochEvi [55]

Tan=o/adj
Tan=60/b
B=60/tan(68)
I don't have a calculator on me but you should be able to do it from there

3 0

2 years ago

during one month the orangevale parks and recreation district spent $5720 for various activities. they spent $1430 on mommy and

AysviL [449]

To solve this problem, we must figure out what percent of the total spending was spent on mommy and baby exercise programs. To figure this out, we should divide how much was spent on the mommy and baby exercise by the total amount spent on the district activities.

$1430/$5720 = 0.25

This is a percentage, or a portion out of 100, which means we must multiply this decimal by 100 to find its equivalent percentage.

0.25 * 100 = 25

Therefore, your answer is 25% of the total spending was spent on mommy and baby exercise programs.

Hope this helps!

5 0

2 years ago

If 4x^2-100=0 the roots of the equation are

Marrrta [24]

Your equation:       4x² - 100   = 0

Factor the left side: (2x + 10) · (2x - 10) = 0

This equation is true if either factor is zero.

-- One factor:    2x + 10 = 0

Divide each side by 2: x + 5 = 0
Subtract 5 from each side: x = -5 .

-- The other factor:       2x - 10 = 0

Divide each side by 2: x + 5 = 0
Add 5 to each side: x =  5 .

8 0

2 years ago

Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n

crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)

= n^2 + n + 2n + 2

= n^2 + 2n + 1 + n + 1

= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0

2 years ago

360 is divisible by which of the following numbers 2,3,4,5,6,9, or 10