The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.
To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.
Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.
<h3>What is the union of events J and K?</h3>
It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.
<h3>What is the complement?</h3>
The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:
15 + x = 58
x = 43.
The number of outcomes that are possible for the complement of the union of Events J and K is of 43.
More can be learned about complementary events at brainly.com/question/9752956
90 ft.......hope this helps
Answer:
1,350
Step-by-step explanation:
45*30=1,350
