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3 years ago

#3: 4(h-3)=52 (Show Work Here!)

Mathematics

1 answer:

NeTakaya3 years ago

3 0

What I did was distribution property
4h-12=52

Now you subtract 12 by both side

4h-12=52
-12 -12

4h=40

Divide 4 by both sides

h=10

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In a carnival game, the player selects a ball one at a time, without replacement, from an urn containing twotwo purplepurple

dezoksy [38]

The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, the possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}

1. Write down the probability distribution for the player earning

The player earning for each event depends on the number of balls drawn subtracted the ticket price.
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
The player earnings would be: 3*$1.5 -$4= $0.5
wwwp= (4*3*2*2)/(6*5*4*3*2)= 2/15
The player earnings would be: 4*$1.5 -$4= $2
wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
The player earnings would be: 5*$1.5 -$4= $3.5

2. Find its expected value

The expected value would be:
chance of event * earning
You need to combine the 5 possible outcomes from the number 1 to get the total expected value.

Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)=
(-12.5 -4 + 1.5 + 4 + 3.5) /15= -$7.5
This game basically a rip off.

6 0

2 years ago

PLZ HEEEELP!!!!! 10 POINTS!!!!

katrin2010 [14]

Answer:

Step-by-step explanation:

Part a

We need two inequalities, one for time worked at each job and the other

for amounts of money earned.

time: Let b and c represent the time (number of hours) worked at babysitting and landscaping respectively. Then b + c ≤ 20 hrs/wk

earnings: Let ($3/hr)(b) represents the amount of money earned babysitting for b hour. Let ($7/hr)(c) represent the money earned working at landscaping. These amounts are per week. The appropriate inequality is ($3/hr)(b) + ($7/hr)(c) ≥ $84 per week. The other inequality is

b + c ≤ 20 hrs/wk.

Part b:

As before, b + c ≤ 20 hrs/wk. What happens if Chet spends all his 20 hours babysitting? To answer this, set c = 0 (no landscaping hours). Then b ≤ 20 hours. At $3/hr, he could earn only $60 and have no time left for landscaping. Not good.

Let's experiment: suppose he works 15 hours babysitting and 5 hours landscaping. His earnings would be $45 + $35, or $80. Still not enough; he wants to earn $84 total. Let's redistribute his time and try again: suppose he works 14 hours babysitting and 6 hours landscaping; his earnings would be $42 + $42, or $84. So {b = 14 hours and c + 6 hours} is a solution. As we continue to reduce the number of hours Chet works babysitting and correspondingly increase those he works landscaping, his earnings will go up, beyond $84.

Here's a table that summarizes this:

babysitting landscaping total amount

hours hours earned

15 5 $60 (not acceptable)

14 6 $84 (borderline acceptable)

12 8 $36 + $42 = $78 (great)

6 14 $116 (greater still)

2 18 $132

1 19 $134

0 20 $140

Summary: Chet can work anywhere from 0 to 14 hours babysitting and expect to earn $84 or more.

4 0

2 years ago

What number can go into 4 and 33

Alex787 [66]

Answer:

Step-by-step explanation:

1 my dude

8 0

2 years ago

Read 2 more answers

Find the equation of the tangent line to the curve y = 2sinx at the point (pi/6,1). The equation of this tangent line can be wri

mixas84 [53]

Y = mx + b

1) m = slope of the tangent line = derivative at the point (pi/6, 1)

Function: y = 2sinx

Derivative: y ' = 2cosx

evaluate at x = pi/6=> y ' = 2cos(pi/6) = √3

2) equation using the slope and the point (pi/6, 1)

y - 1 = √3 ( x - pi/6 )

y = √3 x - √3(pi/6) +1 =√3 x + 0.093

y = √3 x + 0.093

m = √3, b = 0.093

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3 years ago

Today, Sean left home at 8 a.m, drove to work, and worked from 9 a.m.5 p.mOn the drive back home, Sean got stuck in slow-moving

kipiarov [429]

Answer:

-20

-10

Step-by-step explanation:

The graph shows that going from home to work was 20km according to the prompt and it took an hour. The two hours he was stuck in traffic was from 5-7pm and he was moving at 10km an hour again, from the graph. (I'm sorry if this isnt the best explanation, I'm better at getting an answer than explaining it).

8 0

2 years ago