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DanielleElmas [232]
3 years ago
7

I need help with number 5 please !!

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

The answer would be -8000 considering that the opposite of a positive ratio would have to be a negative ratio. If you used absolute value, 8000 and -8000 are the same distance away from zero, so -8000 would be your answer.

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WHOEVER ANSWERS THIS FIRST WITHIN 10 MINUTES GETS VOTED BRAINLIEST
user100 [1]

Answer:

least

x

second least

-1/x

second greatest

x-1

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Step-by-step explanation:

just put -14 where x is and put it in the calculator.

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When you use word processor functions such as spell check and thesaurus to write a second draft you are
nirvana33 [79]
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2 years ago
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X = 3y - 6 2x - 4y = 8 Solve the system of equations using substitution.
Brut [27]
Hello

x = 3y - 6
2x - 4y = 8
We need to start by solving 3y - 6 for x
Substitute 3y -6 for x in 2x
2x - 4y = 8
2(3y - 6) - 4y = 8
2y - 12 = 8
2y = 8 + 12
2y = 20
Divide both sides by 2
2y/2 = 20/2
y = 10

Now, substitute 10 for y in x= 3y
x = 3y - 6
x = 3(10) - 6
x = 30 - 6
x= 24

Answer : x = 24 and y=10

I hope this help!
7 0
3 years ago
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A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1+
egoroff_w [7]

Answer:

a=\frac{3\times 7}{7}+\frac{12}{7}  (First step for obtaining a common denominator for the two fraction)

a=\frac{33}{7}\text{ m/s}^2

Step-by-step explanation:

\text{Given Expression: }a=a_1+\frac{F}{m}

where,

a is acceleration of an object.(Need to calculate)

a_1=3.00\text{ m/s}^2

F=12.0\text{ Kg.m/s}^2

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\text{Substitute }a_1, \text{ F, and m into expression and we get}

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Now we will simplify above expression for a

First we make common denominator.

Common denominator is 7. So, we make both denominator 7. We multiply by 7 at top and bottom with 3. We get

a=\frac{3\times 7}{7}+\frac{12}{7}  (First step for obtaining a common denominator for the two fraction)

Now we combine the numerator

a=\frac{21+12}{7}

a=\frac{33}{7}\text{ m/s}^2



3 0
4 years ago
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