All categories

3 years ago

The last answer choice was dilation pleassee hellpp

Mathematics

2 answers:

Reil [10]3 years ago

7 0

Answer:

its translation

Step-by-step explanation:

Mariana [72]3 years ago

7 0

It’s b no joke and if I it’s not it’s A

You might be interested in

Pls help with this question

Brrunno [24]

I wish i could help but i dont know the answer

7 0

3 years ago

The price of a television was reduced from $250 to $200. What was the percent decrease in price? HELPP? ILL GIVE YOU A BRAINLLES

Diano4ka-milaya [45]

Answer:

20%

I hope this is good enough:

8 0

3 years ago

Find the length of each arc. Round your answers to the nearest tenth. NO LINKS!! Part 1

Hatshy [7]

Answer:
5) 18.8 cm
7) 49.5 ft

Explanation:
The formula for arc length is S = θ * r

5) S = 18 cm * Pi/3 (60 degrees in radians)
S = 6 Pi cm
S ≈ 18.8 cm

7) S = 9 ft * 7 Pi / 4
S = 63 Pi ft / 4
S ≈ 49.5 ft

7 0

3 years ago

Read 2 more answers

PLZ HELP ME I WILL MAKE BRIANLIEST!!

oksian1 [2.3K]

I think it should be 25 blocks east

7 0

3 years ago

You plant a rectangular rose garden along the side of your garage. You enclose 3 sides of the garden with 40 feet of fencing. Th

solmaris [256]

Let's assume

length of rectangle =L

width of rectangle =W

You enclose 3 sides of the garden with 40 feet of fencing

so, we get

$L+2W=40$

now, we can solve for L

$L=40-2W$

we know that

area of rectangle is

$A=L*W$

$100=L*W$

now, we can plug

$100=(40-2W)*W$

now, we can solve for W

$-2W^2+40W-100=0$

we can use quadratic formula

$W=\frac{-40+\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}$

$W=\frac{-40-\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}$

we can take anyone value ..because both are giving positive value

first dimensions:

$W=2.929$

now, we can find L

$L=40-2*2.929$

$L=34.142$

so, length is 34.142feet

width is 2.929 feet

Second dimensions:

$W=17.071$

now, we can find L

$L=40-2*17.071$

$L=5.858$

so, length is 5.858feet

width is 17.071 feet

6 0

3 years ago