Which function describes this graph?

Monica deposits $400 into a savings account that pays a simple interest rate of 4.4%. Paul deposits $500 into a savings accou

DIA [1.3K]

Answer:

From the above calculation it is clear that The interest earn by Monica is less than the The interest earn by Paul , so Monica is wrong

Step-by-step explanation:

Given as :

The principal amount deposited by Monica in account = $ 400

The rate of interest = 4.4 % at simple interest

The time period = 1 years

Let The interest earn by Monica = $ x

From simple interest

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, $ x = $\dfrac{\textrm $ 400\times \textrm 4.4\times \textrm 1}{100}$

Or, x = $ 17.6

So, The interest earn by Monica = x = $ 17.6

Again

The principal amount deposited by Paul in account = $ 500

The rate of interest = 3.6 % at simple interest

The time period = 1 years

Let The interest earn by Paul = $ y

From simple interest

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, $ y = $\dfrac{\textrm $ 500\times \textrm 3.6\times \textrm 1}{100}$

Or, y = $ 18

So, The interest earn by Paul = y = $ 18

∴ As The interest earn by Paul $>$ The interest earn by Monica

Hence from the above calculation it is clear that The interest earn by Monica is less than the The interest earn by Paul , so Monica is wrong Answer

8 0

4 years ago

The triangles are similar.

Elenna [48]

Answer:

x = 12

Step-by-step explanation:

The triangles are similar so we can use ratios

4x+12 32

------- = ------------

15 8

Using cross products

(4x+12) *8 = 15 * 32

(4x+12) *8 = 480

Divide each side by 8

(4x+12) *8/8 = 480/8

4x+12 = 60

Subtract 12 from each side

4x+12 -12 = 60-12

4x = 48

Divide by 4

4x/4 = 48/4

x = 12

8 0

3 years ago

Read 2 more answers

Find the value of each variable A. x=38,y=76 B. x=52,y=76 C. x=38,y=104 D. x=52,y=104

bearhunter [10]

The 2x and 76 are opposite angles so they are equal.

2x = 76

x = 38 degrees

y and 76 are adjacent angles so y = 180 - 76

= 104 degrees

4 0

3 years ago

Find the counterclockwise circulation and outward flux of the field Fequals7 xy Bold i plus 2 y squared Bold j around and over t

77julia77 [94]

Answer:

The counterclockwise circulation is $\frac{7}{12}$ and the outward flux is $\frac{11}{15}$

Step-by-step explanation:

We are given the field $F(x,y) = (7xy,2y^2)$ . A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

$\oint_C F\cdot dr =\iint_R \frac{\partial f}{dy}- \frac{\partial g}{dx} dA$ (this one calculates the counterclockwise circulation)

$\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA$ (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

$\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x$

$\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y$ .

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows $0\leq x \leq 1, x^2\leq y \leq x$ . Then, using the previous results, we get that

$\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12}$ (circulation)

$\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}$ (flux)