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3 years ago

12

Which expressions are equivalent to (b^2)^1/9

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

B

Step-by-step explanation:

When taking an exponent to an exponent

the exponents are multiplied

2*(1/9) = 2/9

B (1/9) * 2 = 2/9

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when buying a new dress, you have the choice of 3 different lengths, 5 different colors, and 2 different styles. How many choice

Thepotemich [5.8K]

Three choice because the choice are all different

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4 years ago

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Use perfect square factoring patterns<br> y^2 + 16y + 64 = 0

Pepsi [2]

Arrange your given equation to resembles the form
a^2 +2ab+ b^2 because this equals (a+b)^2

So we get:
y^2+16y+8^2=0

Now compare
y^2+16y+8^2 to a^2 +2ab+ b^2

So we got
y^2+2•8 y+8^2=0 which equals (y+8)^2

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4 years ago

What ks the % of 4 = 2

Fittoniya [83]

Answer:

$50\%$

Step-by-step explanation:

Let x be the percentage then...

$x\%(4)=2$

Start by dividing both sides by 4:

$x\%=\frac{2}{4}$

Simplify the fraction:

$x\%=\frac{1}{2}$

Then, multiply the fraction by 50/50, so we can get a number over 100 (that number would be the percentage). Note we can only multiply it by 50/50 since it is essentially multiplying the fraction by 1.

$x\%=\frac{1}{2}*\frac{50}{50}\\x\%=\frac{50}{100}\\x=50\%$

4 0

3 years ago

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

4 years ago

How is the solution of 2y=8 related to the solutions of 2y < 8<br> —

enyata [817]

Answer:y=4 and the bottom is boundary point

Step-by-step explanation:

3 0

3 years ago

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