A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
u can not simplefly it doyyyyyyyyyy
YZ since they are in the same spot in the cong statement
Given that a<span>
local RadioShack store wants to buy a new line of plasma TVs.
Manufacturer A offers chain discounts of 18/12, and Manufacturer B
offers terms of 17/13.
Let the list price of the plasma TVs be x, then after a chain discount of 18/12 by Manufacturer A, the selling price of the plasma TVs will be (1 - 0.18)(1 - 0.12)x = 0.82(0.88)x = 0.7216x
Also, after the discount of 17/13 by manufacturer B, the selling price of the plasma TVs will be (1 - 0.17)(1 - 0.13)x = 0.83(0.87)x = 0.7221x
Thus, the final selling price after discount by manufacturer A is 0.7216 and the final selling price after dscount by manufacturer B is 0.7221x.
Therefore, Manufacturer A offers a </span><span>single equivalent discount rate that is the best deal.</span>
Replacement = 11 total
probability of choosing a consonant = 7/11
without replacing the card
probability of choosing an e = 3/10
probability of choosing both = 7/11 * 3/10 = 21/110 <===
