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3 years ago

The Unit Circle

Mathematics

1 answer:

Katen [24]3 years ago

7 0

Answer:

B. 1

Step-by-step explanation:

I calculated it logically

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I think of a number, multiply it by 3 and add 4 and i get 22

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A) 3x+4=22

B) x=6

How to solve the equation: subtract 4 from both sides. You’re left with 3x=18. What is 18 divided by 3?

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3 years ago

An Uber fare is calculated using the formula: Base Fare + (Cost per minute x time of the ride in hours).

pantera1 [17]

Answer:

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Step-by-step explanation:

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20 + (10x3)

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2 years ago

Solve pls<br> 6(n-4)=3n

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8 is the correct answer

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3 years ago

Which description of the graph of the linear equality y > 3x - 8 is correct?

Alexxx [7]

Answer:

Option The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above

the line

Step-by-step explanation:

we have

$y>3x-8$

The solution of the inequality is the shaded area above the dashed line The equation of the dashed line is $y=3x-8$

The slope of the dashed line is positive $m=3$

The y-intercept of the dashed line is -8

see the attached figure to better understand the problem

4 0

3 years ago

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Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?

lys-0071 [83]

Answer:

$cotg(\theta) = -\frac{12}{35}$

Step-by-step explanation:

The cotangent of theta is:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

$sec(\theta) = \frac{1}{\cos{\theta}}$

In this question

$sec(\theta) = -\frac{37}{12}$

$-\frac{37}{12} = \frac{1}{\cos{\theta}}$

Using cross multiplication

$-37\cos{\theta} = 12$

$37\cos{\theta} = -12$

$\cos{\theta} = -\frac{12}{37}$

Now we apply the following trigonometric identity:

$\sin{\theta}^{2} + \cos{\theta}^{2} = 1$

$\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1$

$\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}$

$\sin{\theta}^{2} = 1 - \frac{144}{1369}$

$\sin{\theta}^{2} = \frac{1369 - 144}{1369}$

$\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}$

Since the angle is in the second quadrant, the sine is positive.

$\sin{\theta} = \frac{35}{37}$

Finally, the cotangent:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

$cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}$

$cotg(\theta) = -\frac{12}{35}$

4 0

4 years ago

Read 2 more answers