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3 years ago

I think of a number, multiply it by 3 and add 4 and i get 22

Mathematics

1 answer:

-BARSIC- [3]3 years ago

5 0

A) 3x+4=22

B) x=6

How to solve the equation: subtract 4 from both sides. You’re left with 3x=18. What is 18 divided by 3?

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Vince has a rectangular rug in his room with an area of 10 ft the length of the rug is 18 inches longer than the width what coul

aev [14]

The length of the rug is 4 ft.

The width of the rug is 2.5 ft.

Explanation:

The area of the rug is 10 ft.

The length of the rug be l.

Let us convert the inches to feet.

Thus, $18 inches = 1.5 ft$

Thus, the length of the rug is $l=1.5+w$

Let the width of the rug be w.

Substituting these values in the formula of area of the rectangle, we get,

$A=length\times width$

$10=(1.5+w)(w)\\10=1.5w+w^2\\w^2+1.5w-10=0$

Solving the expression using the quadratic formula,

$w=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Substituting the values, we have,

$$w=\frac{-15 \pm \sqrt{15^{2}-4 \cdot 10(-100)}}{2 \cdot 10}\\$

$w=\frac{-15 \pm \sqrt{4225}}{20}$

$w=\frac{-15 \pm 65}{2 0}$

Thus,

$w=\frac{-15 + 65}{2 0}\\w=\frac{50}{20} \\w=2.5$ and $w=\frac{-15 - 65}{2 0}\\w=\frac{-80}{20} \\w=-4$

Since, the value of w cannot be negative, the value of w is 2.5ft

Thus, the width of the rug is 2.5ft

Substituting $w=2.5$ in $l=1.5+w$ , we get,

$l=1.5+2.5\\l=4$

Thus, the length of the rug is 4 ft.

4 0

3 years ago

Find the remaining trigonometric functions of θ based on the given information.csc θ = 257 and cos θ < 0

katrin [286]

Cos(θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(θ) = 257, but csc(θ) = $\frac{1}{sin(θ)}$ = 257
==> sin(θ) = $\frac{1}{257}$
it is positive, so now we can determine that is in Quadrant 2

sin(θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(θ) < 0
cos(θ) = adj/hyp
Pythereom to find the adj: $257^{2} - 1^{2} = adj ==\ \textgreater \ adj \sqrt{ 257^{2} - 1^{2} } ==\ \textgreater \ adj = 16 \sqrt{258}$

cosθ = $\frac{16 \sqrt{258} }{257} 
$
tanθ = $\frac{1}{16 \sqrt{258} }$
cosθ = $16 \sqrt{258}$