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olga2289 [7]
3 years ago
14

The amount of stretch of a hanging spring versus the mass attached to the bottom of the spring was measured for different masses

. The results are shown in the table. mass (grams) stretch centimeters) 24 48 8 10 16 | 20 What is the constant of proportionality between the mass and the amount of stretch? O 0.5 centimeters per gram O 0.5 grams per centimeter squared O 2.0 centimeters per gram O 2.0 grams per centimeter squared​
Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0

Step-by-step explanation:

j

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Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas
neonofarm [45]

Answer:  The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says "\frac{1}{3} times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

A=b*a

Where "b" is the length of the base  and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2

2. Charlene's rhombus:

A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2

Dividing the area calculated, you get:

\frac{135\ in^2}{15\ in^2}=9

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0
3 years ago
Read 2 more answers
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
3 years ago
The point P(-5,-8) is reflected across the x-axis to create point Q.
Ivahew [28]

Answer:

Answer: D. Q(5, −6) and R(−5, 6)

Step-by-step explanation:

3 0
3 years ago
Given a set of data with the Regression Line: y = 3.5x + 18.5
Tomtit [17]

Answer:

1.5

Step-by-step explanation:

y=3.5*100+18.5=368.5\\rv=370-368.5=1.5

4 0
3 years ago
Simplify by dividing three over five divided by negative four over nine.
Kruka [31]
If I read that right:

(3/5)/(-4/9) is equal to

(3/5)*(9/-4)

-27/20

-1 7/20
3 0
3 years ago
Read 2 more answers
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