Assume the random variable x is normally distributed with mean muμequals=8787 and standard deviation sigmaσequals=55. Find the i

Question

3 years ago

9

ndicated probability. P(x less than<7979)

1 answer:

romanna [79] · Answer 1 · 2022-07-28T01:50:16+03:00

3 0

Answer: 0.4404

Step-by-step explanation:

Let the random variable x is normally distributed .

Given : Mean : $\mu=\ 87$

Standard deviation : $\sigma= 55$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 79

$z=\dfrac{79-87}{55}\approx-0.15$

The p-value = $P(x$

$=0.4403823\approx0.4404$

Hence, the required probability : $P(x$