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ivanzaharov [21]
3 years ago
9

Please simplify (2x^5)^3.

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0
You need to cube the 2 which would give you 8
when you multiply powers from brackets you simply just multiply them

therefore your answer would be 8x^15

hope this helps you
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If line segment AB is 100​%, what is the length of a line segment that is 200​%?
professor190 [17]
2AB ...................
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3 years ago
The mother's age is 8 times her son's age. After 6 years, the age of the mother will be 9/2 times her son's age. The present age
Yakvenalex [24]

Answer:

son = 6 mother = 48

Step-by-step explanation:

Mother = m

son = s

m = 8s

m+6 = 9/2 * (s+6)

so

2(8s + 6) = 9(s +6)

16s + 12 = 9s + 54

16s - 9s = 54 - 12

7s = 42

s = 42/7 = 6 years old

so the mother is 8s = 8*6= 48 years old

4 0
3 years ago
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A number has been round to 7700.what might the number
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3 years ago
What is a corresponding angle?
sasho [114]

Answer:

the angles which occupy the same relative position at each intersection where a straight line crosses two others. If the two lines are parallel, the corresponding angles are equal

Step-by-step explanation:

Just do what i put up there

6 0
3 years ago
Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that
damaskus [11]

Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}

This gives

k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}

Evaluate the quotients

k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

brainly.com/question/14285697

3 0
2 years ago
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