Answer:21 1/8 is the answer
Step-by-step explanation:
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
The negitives are far from the 0 so its less than the non negitives
I believe you would calculate this like so;
We want 18% less than 100% of that amount therefore the single multiplier we would use is as follows:
(100% - 18%) = 82%
Which alternatively = 0.82
Does that make sense? If not I can explain it a bit more. Please let me know.
