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Anton [14]
3 years ago
15

Can you help me with this.

Mathematics
2 answers:
Fudgin [204]3 years ago
7 0

Answer:

1.[opposite side of parallelogram are equal:]

6x-3=x+7

6x-x=7+3

x=10/5=2

x=2

again

y+4=3y+2

4-2=3y-y

y=2/2=1

y=1

2.

[diagonal of parallelogram bisect each other]

8x=24

x=24/8=3

x=3

again

2x+10=3x+4

10-4=3x-2x

x=6

3.

5y-3=2y+36 [alternate angle]

5y-2y=36+3

y=39/3=13

y=13°

4.

8y+11+3y+4=180°[co interior angle]

11y=180-15

y=165/11=15

y=15°

again

7x=3y+4=3×15+4=49° .[opposite angle of parallelogram are equal:]

5..[opposite side of parallelogram are equal:]

7x-10=4x+2

7x-4x=10+2

3x=12

x=12/3

x=4

Ugo [173]3 years ago
5 0

Answer:

1. x = 2

y = 1

2. x = 3 or 6 (Mistake or typo in problem)

3. y = 13

4. x = 7

y = 15

5. x = 4

Step-by-step explanation:

1. 6x - 3 = x + 7, 5x = 10, x = 2

3y + 2 = y + 4, 2y = 2, y = 1

2. There is most likely a typo. Either 8x = 24 and x = 3 or 2x + 10 = 3x + 4 and x = 6

3. 5y -3 = 2y + 36, 3y = 39, y = 13

4. 8y + 11 + 3y + 4 = 180, 11y + 15 = 180, 11y = 165, y = 15

7x = 3y + 4 = 49, x = 7

5. 7x - 10 = 4x + 2, 3x = 12, x = 4

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