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3 years ago

Can you help me with this.

Mathematics

2 answers:

Fudgin [204]3 years ago

7 0

Answer:

1.[opposite side of parallelogram are equal:]

6x-3=x+7

6x-x=7+3

x=10/5=2

x=2

again

y+4=3y+2

4-2=3y-y

y=2/2=1

y=1

[diagonal of parallelogram bisect each other]

8x=24

x=24/8=3

x=3

again

2x+10=3x+4

10-4=3x-2x

x=6

5y-3=2y+36 [alternate angle]

5y-2y=36+3

y=39/3=13

y=13°

8y+11+3y+4=180°[co interior angle]

11y=180-15

y=165/11=15

y=15°

again

7x=3y+4=3×15+4=49° .[opposite angle of parallelogram are equal:]

5..[opposite side of parallelogram are equal:]

7x-10=4x+2

7x-4x=10+2

3x=12

x=12/3

x=4

Ugo [173]3 years ago

5 0

Answer:

1. x = 2

y = 1

2. x = 3 or 6 (Mistake or typo in problem)

3. y = 13

4. x = 7

y = 15

5. x = 4

Step-by-step explanation:

1. 6x - 3 = x + 7, 5x = 10, x = 2

3y + 2 = y + 4, 2y = 2, y = 1

2. There is most likely a typo. Either 8x = 24 and x = 3 or 2x + 10 = 3x + 4 and x = 6

3. 5y -3 = 2y + 36, 3y = 39, y = 13

4. 8y + 11 + 3y + 4 = 180, 11y + 15 = 180, 11y = 165, y = 15

7x = 3y + 4 = 49, x = 7

5. 7x - 10 = 4x + 2, 3x = 12, x = 4

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2 years ago

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FromTheMoon [43]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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Gemiola [76]

Answer:

A. (3, 8) and $2\sqrt{2}$

B. (2, 4) and $2\sqrt{10}$

Step-by-step explanation:

Midpoint formula: $(\frac{x1+x2}{2} ,\frac{y1+y2}{2})$

Distance formula: $\sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }$

A. plug in the points in the formulas

(4, 7) and (2, 9)

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$(\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)$

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(5, 5) and (-1, 3)

Midpoint:

$(\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)$

Length:

$\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}$

Can you consider marking my answers as brainliest lol it would mean a lot. Hope this helped.

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2 years ago