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icang [17]
3 years ago
6

I’m not sure how to use integration to solve this question (4)

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
Hello,
Area= \frac{16}{3}=2*( k*\sqrt{k}- \int\limits^{\sqrt{k}}_{0} {x^2} \, dx )\\\\

 \dfrac{8}{3}=k ^\frac{3}{2}- \frac{1}{3}* [x^3]^{\sqrt{^k}}_0\\\\
2* k ^\frac{3}{2}=8\\\\

k = \sqrt[3]{16}\\





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