All categories

2 years ago

Im cond=fused on it and really need help to continue to pass my classes

Mathematics

2 answers:

skad [1K]2 years ago

7 0

Ok , what do you need help with

maxonik [38]2 years ago

4 0

Answer:

http://www.calcul.com/show/calculator/recurring-decimal-to-fraction?i=0.02...

Step-by-step explanation:

You might be interested in

List the following numbers in order from least to greatest. 2, -3, 9 what is this

scoundrel [369]

-3, 2, 9 hope this helpedd

6 0

2 years ago

Read 2 more answers

The circumference of circle p is 800 mm, the circumference of circle q is 200 cm, and the circumference of circle r is 4 m. What

shepuryov [24]

Let us use the following conversions:

1 cm = 10 mm

1 meter = 100 cm = 1000 mm

Given:

p = 800 mm

q = 200 cm = 2000 mm

r= 4 m = 4000

X = sum of the distance around each circle

X = p+q+r

X = 800+2000+4000

X = 6800 mm or 680 cm or 6.80 m

7 0

2 years ago

The interior angles of a triangle are

lbvjy [14]

Answer:

$8x+13y = 130$

Step-by-step explanation:

sum of interior angles in a triangle is 180 degree

interior angles are (5x+3y)∘,(3x+20)∘, and (10y+30)

add all the angles and make it equal to 180

$5x+3y+3x+20+10y+30= 180$

combine like terms

$5x+3y+3x+20+10y+30= 180$

$8x+13y+x+50= 180$

subtract 50 from both sides

$8x+13y = 130$

4 0

2 years ago

Question below

Ksivusya [100]

Answer:

$m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]$

Step-by-step explanation:

Calculate the value of m

Given:

$3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]$

Therefore:

$\implies 3=\dfrac{2}{3}m$

$\implies m=3 \times \dfrac{3}{2}$

$\implies m=\dfrac{9}{2}$

Calculate the value of H

Given:

$\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)$