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tangare [24]
3 years ago
6

A normal distribution has a mean of 14 and a standard deviation of 4. What percent of values are from 14 to 22?

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0

Answer:

80% of the values will occurs above 68.24.

Step-by-step explain

thinking this is right but im sorry if its wrong

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A class consists of 1/2 freshmen, 1/8 sophomores, and 1/8 juniors; the rest are seniors. What fraction of the class is seniors?
Firlakuza [10]

Answer:

2/8

Step-by-step explanation:

freshman=4/8

1/8 soph    1/8 jr

add all together u get 6/8

the rest is seniors so its 2/8

8 0
3 years ago
Oomygawd plz help me with this math hw
aev [14]

Hi There!

------------------------------------------------

Slope Intercept Form: y = mx + b

Where: m = slope and b = y-intercept

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Question 11: The slope being 0.5 is the pay for the amount of miles he pays daily.

Question 12: y = 2x + 20

Question 13: y = 25x + 50

Question 14: y = 1/2x + 6

Question 15: y = 2x + 15

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6 0
3 years ago
What is A- 3.5= 14.9
gladu [14]
A = 14.9 +3.5 = 18.4 :D

7 0
2 years ago
The table represents a linear function.<br> What is the slope of the function?
TEA [102]

Answer:

-4

Step-by-step explanation:

The function is linear; therefore, the slope of the line joining any two points is the same.

We take any two points from the table and compute the slope or  rise/ run between them— let is take points (-4, -2) and (-2, -10).

The slope m of the line joining the points is

m=\dfrac{\Delta y }{\Delta x } =\dfrac{-2-(-10)}{-4-(-2)} \\\\\boxed{m=-4}

The slope of the function is -4.

3 0
2 years ago
Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
2 years ago
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