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azamat
4 years ago
9

Which biconditional is NOT a good definition ?

Mathematics
1 answer:
alexgriva [62]4 years ago
6 0

Answer:

d

Step-by-step explanation:

An angle is straight if and only if its measure is 180

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It would be 10 hours but the distance would be 260 mph.
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What 18/25 simplest form?
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It is already simplified because there is nothing you can divide into both 18 and 25 that would result in whole numbers.
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How do you factor quadratics into binomials
fomenos

Answer:

Step-by-step explanation:

Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.

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8 0
3 years ago
20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that
IRINA_888 [86]

<u>ANSWER:  </u>

The algebraic expression for number of ribbons is \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into 7\frac{1}{2} inches or 6\frac{3}{4} inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}

\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right ]

So, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}

So, the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

Hence, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

5 0
3 years ago
In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.
Hitman42 [59]

\longmapstoThe value of "x" is 5.

\large\underline{\sf{Solution-}}

Given that,

A trapezium ABCD in which AB || CD such that

  • AO = x - 1

  • CO = BO = x + 1

  • OD = x + 4

Now,

\rm In \: \triangle  \: AOB  \: and \: \triangle \:  COD

\rm  \: \angle  \: AOB  \: and \: \angle \:  COD \:  \:  \{vertically \: opposite \: angles \}

\rm  \: \angle  \:ABO  \: and \: \angle \:  CDO \:  \:  \{alternate \: interior \: angles \}

\bf \: \triangle  \: AOB \:  \sim \:  \triangle  \: COD \:  \:  \:  \{AA \: similarity \}

\bf\longmapsto\:\dfrac{AO}{CO}  = \dfrac{BO}{DO}

\rm \longmapsto\:\dfrac{x - 1}{x + 1}  = \dfrac{x + 1}{x + 4}

\rm \longmapsto\:(x - 1)(x + 4) =  {(x + 1)}^{2}

\rm \longmapsto\: {x}^{2} - x + 4x - 4 =  {x}^{2} + 1 + 2x

\rm \longmapsto\: 3x - 4 =  1 + 2x

\rm \longmapsto\: 3x  -  2x=  1 +4

\bf\longmapsto \:x = 5

7 0
3 years ago
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