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azamat
3 years ago
9

Which biconditional is NOT a good definition ?

Mathematics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

d

Step-by-step explanation:

An angle is straight if and only if its measure is 180

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What values of x and y satisfy the system of equations {3x+2y=14x=4y−2? infinitely many solutions (5011,1811) (1811,5011) no sol
irinina [24]
3x+2y=14x=4y-2

(x,y)=(1/4,11/8)
8 0
3 years ago
Write the equation of the line in slope-intercept form using y=mx+b​
adelina 88 [10]

Answer:

y = 1/2x+2

Step-by-step explanation:

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3 years ago
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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
3 years ago
Read 2 more answers
X + 3/2= 2 1/4 whats the answer
kicyunya [14]

Move all terms not containing x to the right side of the equation.

Exact Form:

x=15/4

Decimal Form:

x=3.75

Mixed Number Form:

x=3 3/4

hope this helps

5 0
2 years ago
Can anybody help me solve this? You must solve for X first.
gogolik [260]

Answer:

45 degrees

Step-by-step explanation:

angle QRS is same as (2x + 3) because it is an isosceles triangle

so, 90 + (2x+3) + (2x+3) =180 degrees

             2x+3 +2x+3=180-90

2x+2x +3+3=90

4x+6=90

4x=90-6

4x=84

x=84/4

x=21

substitute x=21 in (2x+3)

2*21+3=45

6 0
3 years ago
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