All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is
Multiply both sides by <em>r</em> :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for 
:
Then as gets arbitrarily large, the term 
will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer:
in the ordered pair; ( x = 27/4 , y = 1/4 )
Step-by-step explanation:
Given that:
The system of the equation shown below is:
-2x - 14y = 10
2x + 2y = 14
We are to use the elimination method to determine the ordered pair.
From the above equation:
-2x - 14y = 10 --- (1)
2x + 2y = 14 --- (2)
Add both equation 1 and 2 together in order to eliminate x, then we can solve for y first.
-2x - 14y = 10
<u> 2x + 2y = 14 </u>
<u> 0 - 16y = -4 </u>
<u />
- 16 y = - 4
divide both sides by - 16, Then:
-16y /-16 = -4/-16
y = 1/4
Since y = 1/4, Then from equation (2), x will be :
2x + 2y = 14
2x + 2(1/4) = 14
2x + 1/2 = 14
2x = 14 - 1/2
2x = 13.5
x = 13.5/2
x = 27/4
Thus, in the ordered pair; ( x = 27/4 , y = 1/4 )
Answer:
5^3
Step-by-step explanation:
Answer:
3 a penny 4 a penny 5 a penny 6 a penny
Step-by-step explanation:
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