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Anit [1.1K]
3 years ago
7

the sum of two numbers is 48, difference is 14. find the numbersthe sum of two numbers is 48 and their difference is 14 what are

the two numbers
Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0
The answer is 17 and 31
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In which quadrant is the number –14 – 5i located on the complex plane?
AlekseyPX
On the complex plane, the real component of a complex number is graphed along the horizontal axis while the imaginary component is graphed along the vertical axis.

Positive numbers go to the right on the real axis and up on the imaginary axis, and vice versa for negative numbers.

Therefore, the number -14-5i is in the 3rd quadrant because it graphed to the left of the origin and down.
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3 years ago
Insert grouping symbols <br><br> 2 times 9+7
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Answer:

2 times (9+7)

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Factor 2y^2+7y-14=0<br> How do I solve this by factoring ?
Gre4nikov [31]

Answer:

y=−7−(√161/4), −7+(√161)/4

Decimal form- y=1.42214438, -4.92214438

Step-by-step explanation:

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3 years ago
Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)
kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios  between two points (x1,f(x1)) and (x2,f(x2)) is

  • ARC = [f(x2)-f(x1)]/ (x2-x1)

<em>In case a)</em>

f(-1)= -5*(-1)-8=5-8= -3          f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

<em>In case b)</em>

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

<em>In case c)</em>

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0
3 years ago
Find the domain of f(x) =√3x-1
maw [93]

Answer:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

( − ∞ , ∞ )  

{x | x  ∈  R }


Hope this helps I'm 80% sure this right.



4 0
3 years ago
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