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3 years ago

PLEASE HELP ME I DONT UNDERSTAND!

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

7 0

We know that

$\sf Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Slope = -4 - 5/-2 - 1

Slope = -9/-3

Slope = 3/1

Slope = 3

Hence,

Slope is 3

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Please help! 70 points :) Will award brainliest

dexar [7]

Answer:

38 = FH

Step-by-step explanation:

Because this is a rectangle, IG = FH

We know that IE + EG = FH

We also know that IE = EG (perpendicular bisectors)

IE = EG

3x+4 = 5x-6

Subtract 3x from each side

3x-3x+4 = 5x-3x-6

4 = 2x-6

Add 6 to each side

4+6 =2x

10 =2x

Divide by 2

10/2 =2x/2

5=x

Now lets find FH

IE + EG = FH

3x+4 + 5x-6 = FH

Combine like terms

8x-2 = FH

Substitute in x =5

8*5-2

40-2

38 = FH

7 0

3 years ago

Read 2 more answers

In ATUV, Y is the centroid. If TY = 30, what is YW? A.15 B.45 C.30 D.60

skelet666 [1.2K]

We know at centroid medians bisect each other in the ratio 2:1.

TY=30
Let YW be x

$\\ \sf\longmapsto TY=2x$

$\\ \sf\longmapsto 2x=30$

$\\ \sf\longmapsto x=\dfrac{30}{2}$

$\\ \sf\longmapsto x=15$

8 0

2 years ago

Read 2 more answers

Pls solve no;3a,b,c the picture will be given thank u use trigonometry u solve it

elena-14-01-66 [18.8K]

Answer/Step-by-step explanation:

3.a. length of AC.

Hypotenuse = AC

Opposite side to 60° = 7

Therefore, $sin(60) = \frac{7}{AC}$

$AC*sin(60) = \frac{7}{AC}*AC$

$AC*sin(60) = 7$

$AC = \frac{7}{sin(60)}$

$AC = 8.1$ (to nearest tenth)

b. Length of BC

Hypotenuse = BC

Opposite side to 50° = 7

Therefore, $sin(50) = \frac{7}{BC}$

$BC*sin(50) = \frac{7}{BC}*AC$

$BC*sin(50) = 7$

$BC = \frac{7}{sin(50)}$

$BC = 9.1$ (to nearest tenth)

c. Length of AB

Use the law of sines to find AB

$\frac{BC}{sin(A)} = \frac{AB}{sin(C}}$

m<C = 180 - (60 + 50) (sum of angles in a triangle) = 70°

m<A = 60°

BC = 9.1

AB = ?

$\frac{9.1}{sin(60)} = \frac{AB}{sin(70)}$

Cross multiply

$9.1*sin(70) = AB*sin(60)$

Divide both sides by sin(60)

$\frac{9.1*sin(70)}{sin(60)} = \frac{AB*sin(60)}{sin(60)}$

$\frac{9.1*sin(70)}{sin(60)} = AB$

$9.9 = AB$ (nearest tenth)

$AB = 9.9$

8 0

3 years ago

The correlation between a car’s engine size and its fuel economy (in mpg) is r = - 0.774.

fgiga [73]

Answer: 59.91%.

Step-by-step explanation:

We know that the fraction of the variability in data values accounted by a model is given by $r^2$ , where r is the coefficient of correlation.

We are given , that the correlation between a car’s engine size and its fuel economy (in mpg) is r = - 0.774.

Then, the fraction of the variability in fuel economy is accounted for by the engine size would be $r^2=( - 0.774)^2=0.599076\approx59.91\%$

[Multiply 100 to convert a decimal into percent]

Hence, the fraction of the variability in fuel economy is accounted for by the engine size is 59.91%.

None of the options are correct.

5 0

3 years ago

Are the expressions 5(4x+3) and 20x+3 equivalent

Alika [10]

Answer:

Step-by-step explanation:

5(4x+3) = 20x+15 which isnt 20x+3

8 0

3 years ago