Not sure. I would say no.
To find the diagonal of the rectangle we have to use Pythagorean theorem!
Pythagorean theorem is used to find the length of a missing angle such as the hypotenuse or the sides a and b.
Steps to solve:
1. 12 in is the length or the base of the right triangle, and 6 in is the wide or the side a.
2. Now use the formula: a^2+b^2=c^2, and plug in the numbers!
3. 6^2+12^2=c^2, now just solve the squared numbers.
4. 36+144=c^2
5. 180=c^2
6. Find the square root of 180.
And that is you answer!
If helped mark me the brainiest!!
Using algebraic expressions, the value of x in the diagram given is calculated as: x = 4
<h3>What is an Algebraic Equation?</h3>
An algebraic equation is an equation that has an unknown variable (i.e. x) and digits, which can be used to solve a problem.
Algebraic expression for Mat A is: 4x + 3
Algebraic expression for Mat B is: 2x + 11
We would have the following algebraic equation:
4x + 3 = 2x = 11
Solve for the value of x
4x - 2x = 11 - 3
2x = 8
x = 8/2
x = 4
Learn more about algebraic equations on:
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The answer is D. 5 and 6
Hope it helped!
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8
