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sineoko [7]
3 years ago
5

There were 450 students enrolled in a middle school at the beginning of the school year. The number of students enrolled in the

school at the end of the year was 10 percent less than the number of students enrolled in the school at the beginning of the year.
How many students were enrolled in the school at the end of the year?​
Mathematics
2 answers:
taurus [48]3 years ago
8 0

Answer:

405

Step-by-step explanation:

10% of 450 is 45 and 450-45=405 students

3241004551 [841]3 years ago
6 0

Answer:

405 maybe?

Step-by-step explanation:

10% of 450 is 45 and subtract that from 450?

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Kenya exchanges $200 for euros (€). Suppose the conversion rate is €1 = $1.321. How many euros should Kenya receive? (1 point)
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What is the slope of this graph?
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Answer:  1/5 up 1 over 5

Step-by-step explanation:

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10 POINTS! Answer ASAP
ratelena [41]

m5=75 degrees

m11=75 degrees

m16=65 degrees

To find 5, realize angles 5 and 8 equal 180, because they make up a straight line, line d.

180-105=75

To find 11, it is the same as finding 7. Just look at the similar sizes. Angle 7 is the same at angle 5, just turned around. There’s a term for this pair angles that I don’t remember now but it exists. Now, lines a and b are parallel, so their angles between lines that intersect both are the same too. This means, as angle 5 equals angle 7, angle 7 equals angle 11.

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8 0
3 years ago
A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

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3 years ago
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