Answer:
Using the estimate:
The car has to go for 1,200 miles but it consumes a gallon of gasoline for every 30 miles. The number of gallons it will need is therefore:
= 1,200 / 30
= 40 gallons
Each gallon costs $3.00 so the total cost is:
= 40 * 3
= $120
Without using the estimate:
The car has to go for 1,211 miles but it consumes a gallon of gasoline for every 29 miles. The number of gallons it will need is therefore:
= 1,211 / 29
= 41.76 gallons
Each gallon costs $3.40 so the total cost is:
= 41.76 * 3.40
= $141.98
<em>Using the estimate provides a lower cost of gasoline for the trip. </em>
Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:
item i:
Velocity is the <u>derivative of the position</u>, hence:
Item ii:
The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:
Item iv:
The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:
Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
cost of large delivery truck = $60,000
cost of small delivery truck = $45,000
Step-by-step explanation:
let,
the cost of large delivery truck = 'x'
the cost of small delivery truck = 'y'
Now, according to the question,
3x + 2y = 270000
4x + 3y = 375000
By solving the above 2 equation , we get;
x = 60000
y = 45000
To find the simple interest, we multiply 600 × 0.04 × 1.5 to get that:
The interest is: $36.00
I believe B,C, and D is correct...
please vote my answer brainliest. thanks!
