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zysi [14]
3 years ago
11

How to add the integers -7 and -5.

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0
-7 + -5
When you add negative, it would be the same as subtracting
Turns into: -7-5
-(7+5) = -12
The solutions is -12
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Well range is the difference between the highest and lowest numbers so 20-7 is 13
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4 years ago
Find the measure of angle x in the figure below: A.) 65° B.) 70° C.) 110° D.) 125°
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Answer: 70ᴼ

Step-by-step explanation:

The triangles are vertical so their angle measures are congruent.

The angles of a triangle add to equal 180ᴼ.

55 + 55 = 110

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How do u solve the quadratic equation x^2-x-2?
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6 0
4 years ago
On a tuesday a magician said i made my wife disappear 31 days ago what day of the week did he make her disappear
kap26 [50]

Answer:

Saturday.

Step-by-step explanation:

To answer the above question, we must recognise that Tuesday appears once every 7 days.

If today is Tuesday, 31 days ago will be obtained as follow:

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31 = (7 × 4) + 3

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Thus, the 28th day is Tuesday. If we count 3 days back from Tuesday, the day will be Saturday.

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8 0
3 years ago
Please help it's due today. Also please don't help if you don't know.​
zhannawk [14.2K]

Answer:

D) 8g^{6} h^{4} k^{12} -h^{25}k^{15}

Step-by-step explanation:

You have to use the laws of exponents to solve this:

Power of a Power: (a^{m} )^{n} = a^{mn}. In this case, (4g^{3} h^{2} k^{4} )^{3}, all of the numbers in the parenthesis need to be multiplied to the power of 3: 4^{3} g^{9} h^{6} k^{12}.

Quotient of Powers: \frac{a^{m} }{a^{n} } = a^{m-n}. In this case, \frac{4^{3} g^{9} h^{6} k^{12}}{8g^{3} h^{2} }, all of the exponents need to be subtracted (but the 4³ (64) and 8 need to be divided): 8g^{6} h^{4} k^{12}.

Use the Power of a Power again for the expression at the right: (h^{5} k^{3} )^{5}. You get: h^{25} k^{15}. Keep the subtraction/negative sign where it is.

Together, you get: 8g^{6} h^{4} k^{12} -h^{25}k^{15}.

Hope it helps!

6 0
3 years ago
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