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3 years ago

Mason used 1/5 of a liter of water to fill 1/8 of an aquarium. How much water, in liters, is required to fill the aquarium?

Mathematics

1 answer:

kkurt [141]3 years ago

5 0

Answer:

$\frac{8}{5} = 1 \frac{3}{5}$

Step-by-step explanation:

8 x 1/5 = 8/5

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A new youth sports center is being built in a safe harbor. The perimeter of the rectangular playing field is 510 yards. The leng

podryga [215]

Answer:

<h2>L=203 yards</h2><h2>W=52 yards</h2>

Step-by-step explanation:

Step one:

given data

perimeter= 510 yards

let the width be x, width=x

length= (4x-5)-----quadruple mean 4 times

Step two:

the expression for perimeter is

P=2L+2W

510=2(4x-5)+2x

510=8x-10+2x

510+10=8x+2x

520=10x

divide both sides by 10

x=520/10

x=52

the width is 52 yards

the lenght is (4x-5)

L=4(52)-5

L=208-5

L=203 yards

4 0

3 years ago

Which length is 10 6 times greater than a nanometer?

crimeas [40]

A nanometer (nm) is 10⁻⁹ m.

Therefore
10⁶ x 1 nm = 10⁶(10⁻⁹ m) = 10⁻³ m

By definition,
10⁻³ m = 1 mm (millimeter)

Answer: 1 millimeter

8 0

3 years ago

Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem. A cube-shaped box has

aev [14]

Using the given equation and edge length:

V = 45^3

V = 45 x 45 x 45

V = 91,125 cubic meters

3 0

3 years ago

Evaluate the following expression will give branliest<br> 256 to the power of 5/8

Nana76 [90]

Answer:

Step-by-step explanation:

The formula needed to solve this question by hand is:

$x^{\frac{m}{n}} =\sqrt[n]{x^{m}}$

256^(5/8) = 8th root of 256^5

256^(5/8) = 8th root of 1280

5 0

3 years ago

Read 2 more answers

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many

Phantasy [73]

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022\times 10^{23}$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022\times 10^{11}$ trillion sand particles is

$Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^{3}$ thus the volume of 1 mole of sand is volume of $6.022\times 10^{23}$ sand particles

Thus volume of 1 mole is $V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}$

Now since the Area of united states is $A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}$

Thus the depth of the sand pile is

$Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters$

4 0

3 years ago